Maths Number System
Find number of zeroes at end of: 1!×(1×2)!×(1×2×3)! i.e. 1!×2!²×3!³×...×10!¹⁰ (i.e. 1¹×2²×3³...×10¹⁰ factorials)
1!¹×2!²×3!³×...×10!¹⁰ के अंत में शून्यों की संख्या ज्ञात कीजिए:
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A
(a) 10!+15!
B
(b) 5!+10!
C
(c) 20!
D
(d) 15!
Correct Answer: Option A
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Explanation / व्याख्या:
Zero-contributing terms: 5! and 10! raised to their powers. Total zeros=5!+10!.
शून्य देने वाले पद: 5! और 10!। कुल=5!+10!।
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